Question

A block of mass m slips on a rough horizontal table under the action of a horizontal force applied to it. The coefficient of friction between the block and the table is μ. The table does not move on the floor. Find the total frictional force applied by the floor on the legs of the table. Do you need the friction coefficient between the table and the floor or the mass of the table?
Figure

Answer 1

The gross frictional force on the floor table is μmg.

Explanation:

Step 1:

The free body diagram shows the maximum frictional force acting on it when a block slips on a rough horizontal table:

R = mg (If the lift is still, or moving at constant velocity, then  W = mg = R )

M is mass  

acceleration due to gravity, g

Step 2:

The friction coefficient between block and table is μ

From the image of the body,  

F − μR

F = μR = μmg

Step 3:

But the table is at rest, so μR is also the frictional force on the table legs.  

Let this be f, so from the map of the free body

f − μR = 0

f = μR = μmg

The gross frictional force on the floor table is therefore μmg.

Answer 2

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Please refer the above attachment