Question

A block of mass m slips on a rough horizontal table under the action of a horizontal force applied to it. The coefficient of friction between the block and the table is µ. The table does not move on the floor . Find the total frictional force applied by the floor on the legs of the table. Do you need the friction coefficient between the table and the floor or the mass of the table?Concept of Physics - 1 , HC VERMA , Chapter 6:Friction "

Answer 1

Solution :
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Because The block slips on the table, maximum frictional force acts on it.
From the free body diagram.
R=mg
F-μR=0
F=μR=μmg
But the table is at rest, so frictional force at the legs of the table is also μR1
Let f be the frictional force , from free body diagram:
f-μR=0
f=μR=μmg
∴The total frictional force on the table by floor is μmg

Answer 2

HEY!!

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⚫⚫When a block slips on a rough horizontal table, the maximum frictional force acting on it can be found from the free body diagram:-

✅R = mg

⚫From the free body diagram, 
F − μR = 0

⚫F = μR = μmg

⚫But the table is at rest, so the frictional force at the legs of the table is also μR.

⚫Let this be f, so from the free body diagram
f − μR = 0

⚫f = μR = μmg

▶️▶️Therefore, the total frictional force on the table by the floor is μmg.