Question

A block of mass M suspended by an ideal thread from a rigid support is pulled by a horizontal force F. The thread deflects through an angle theta . Then​

Answer 1

Explanation:

A block of mass M suspended by an ideal thread from a rigid support is pulled by a horizontal force F. The thread deflects through an angle theta .

Answer 2

Answer: Value of angle theta is  $tan^{-1}(\frac{F}{Mg} )$

Explanation:

There are three forces acting on the block : Tension in thread , earth's gravitational pull and applied external horizontal force F.

The block deflects by angle theta and attains equilibrium.

In equilibrium,  net force on the block should be zero.

Balancing the forces in horizontal direction :

F = Tsinθ   ...eq(1)

Balancing the forces in vertical direction :

Mg = Tcosθ  ....eq(2)

Dividing eq(1) by eq(2), we get :

$\frac{F}{Mg} = tan\theta$

$\theta = tan^{-1}(\frac{F}{Mg} )$

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