Question

A block of mass mis lying at the bottom of a smooth inclined plane. Forces F1 and F2 are acting on the block as shown in figure. The block is moved to the top of inclined plane (of length x) with constant speed.

The net work done by the forces F1 and F2 is​

Answer 1

hope it helps you pls like follow and mark me brainliest

Answer 2

Explanation:

Hint: Work done by all forces is equal to change in kinetic energy.

Sol.: Work done by forces  + work done by gravity = ΔK = 0

work done by  

work done by  = mgh

Hope it helps....✌️✌️✌️

pls mark as brainliest!!!!!!!!!!!!!!!!