a block of mass of 2 kg is placed on the floor. the coefficient of static friction is 0.4 . a force F of 2.5 N is applied on the block. calculate the force of friction between the block and the floor.
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µs = 0.4
m = 2 kg
F = 2.5 N
Maximum static frictional force,
fmax = µs × m × g
= 0.4 × 2 × 9.8
= fmax = 7.84 N
m = 2 kg
F = 2.5 N
Maximum static frictional force,
fmax = µs × m × g
= 0.4 × 2 × 9.8
= fmax = 7.84 N
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