A block of mass of 5 kg is at rest water coming out of pipe horizontally at the rate of 3kg/s hits the block with velocity 6m/s the initial acceleration of the block is
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Explanation:
f=dm/dt×v
f=3×6=18N
(f=ma),, 18= 5a
a=18/5
a=3.6m/s^2
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