Question

a block of material with relative density 1/3 is submerged in water. it starts moving up with acceleration 'a'. find the value of 'a'. (g is the acceleration due to gravity).​

Answer 1

A block of material with relative density 1/3 is submerged in water. It starts moving up with acceleration a. The value of a is 2g

Option (2) is correct.

Explanation:

Let the mass of the block be M

If the density of the liquid is $\rho$, the density of the block will be $=\frac{\rho}{3}$

Volume of the block

V= Mass/Density

$\implies V=\frac{M}{\rho/3}$

$\implies V=\frac{3M}{\rho}$

The volume of the liquid displaced will be V

The bouyant force will be equal to $V\times \rho\times g$

The net force on the block in the upward direction

$F=V\rho g-Mg$

$\implies F=\frac{3M}{\rho}\times \rho g-Mg$

$\implies F=2Mg$

Therefore, the net acceleartion in the upward direction

$a=\frac{F}{M}$

$\implies a=\frac{2Mg}{M}$

$\implies a=2g$

Hope this helps.

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Answer 2

Answer:

2g

Explanation:

hope it helps...☺☺