Question

A block of metal weighing 2 kg is resting
on a frictionless plane. is struck by a jet
releasing water at a rate of 1 kg/sec and at
a speed of 5 m/sec. The initial acceleration
of the block will be?​

Answer 1

Answer:

(5/2) m/s²

Explanation:

The force exerted by water jet,

F = v(dm/dt) = (5m/s)(1kg/s) = 5kgm/s²

We know, F = ma => a = F/m = (5kgm/s²)/2kg = (5/2) m/s²

Answer 2

Answer :-

F = v dm/dt

= 5 x 1

= 5N

acceleration= a = F/m

= 5/2

= 2.5 ms⁻²