Question

a block of metal weighing 2 kg is resting on a frictionless plane it is struck by a jet releasing water at a rate of one kg per second and at a speed of 5 metre per second the initial acceleration of the block will be

Answer 1

Given,

m = 2 kg

rate of water (dm/dt) = 1 kg/sec

We know that,

$F = v \frac{dm}{dt} \\ \\ F = 5 \times 1 \\ \\ F = 5 N \textbf{According to newton's second law} \\ \\ F = ma \\ 5 = 2 \times a \\ \\ a =2.5 \ m\sec^{2}$

Answer 2

Answer:

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