Question

A block of silver of mass 4 kg hanging from a string is increased in a liquid of relative density 0.75 relative density of silver is 10 and the tension in the string the baby

Answer 1

By using density = mass/volume we can find the volume of the Silver cube,

10 = 4/v

v = 4/(10Ρw) m^3 ;           Ρw - Density of water

Then from Archimedes' principle,

upward buoyant force (U) = weight of the fluid that the Silver cube displaces

                                         = 0.75Ρw x 4/10Ρw x g

                                         = 3/10

                                         = 0.3 N

Then,

T + U = mg ; T - tension of the string

T   = mg - U

    = 4x10 - 0.3

 T   = 39.7 N

Answer 2

Answer:

Explanation:

Use formula (ps-pl)Vg

Take V= mass/density

Answer is 37.12N