Question

a block of size 20 m × 10 m × 25 m exerts a force of 30 N and calculate the maximum and minimum pressure exerted by a block on a ground

Answer 1

Heya!!

★Answer★
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→As We Know,Force Is Constant ,

Pressure ∞ 1/Area

Now, Calculating The Area Of Three Faces,
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A1 =(20 × 10)

→A1=200 sq. m
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A2=(10 × 25)

→A2=250sq. m
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A3=(20 × 25)

→A3=500 sq. m
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Now, A1 Is Minimum And A2 Is Maximum.

∴Minimum Pressure

= F/A2

=30/250

=0.12 N/m^2

∴Maximum Pressure

=F/A1

=30/200

=0.15 N/m^2

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Hope Helped (:

Answer 2

$\large{\boxed{\red{\textbf{ Thanks\:For\:Ansking}}}}$

We know, when force is constant, pressure ∞ 1/Area.

Therefore, pressure is maximum when area is minimum and vice versa.

By calculating the area of three faces, we get,

⇒A₁ = (20×10)= 200 sq m.

⇒A₂ = (10×25) = 250 sq m.

⇒A₃ = (20×5) = 100 sq m.

∴ A₁ is maximum and A₂ is minimum.

∴ Minimum pressure P₁ = F/A₁ = 30/200 = 0.15 Nm⁻².

∴ Maximum pressure P₂ = F/A₂ = 30/50 = 0.6 Nm⁻². (Ans)