Question

a block of size 20 m x 10 m x 5 m exerts a force of 30 N. calculate the maximum and minimum pressure exerted by block on ground...

Answer 1

pressure=F/A
force is 30 N
pressure is inversely proportional to area
max pressure=30/50=0.6
min pressure=30/200=0.15

Answer 2

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We know, when force is constant, pressure ∞ 1/Area.

Therefore, pressure is maximum when area is minimum and vice versa.

By calculating the area of three faces, we get,

⇒A₁ = (20×10)= 200 sq m.

⇒A₂ = (10×5) = 50 sq m.

⇒A₃ = (20×5) = 100 sq m.

∴ A₁ is maximum and A₂ is minimum.

∴ Minimum pressure P₁ = F/A₁ = 30/200 = 0.15 Nm⁻².

∴ Maximum pressure P₂ = F/A₂ = 30/50 = 0.6 Nm⁻². (Ans)