a block of size 20m×10m×5m exerts a force of 30 N calculate the maximum and minimum pressure exerted by block on ground
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We know, when force is constant, pressure ∞ 1/Area.
Therefore, pressure is maximum when area is minimum and vice versa.
By calculating the area of three faces, we get,
⇒A₁ = (20×10)= 200 sq m.
⇒A₂ = (10×5) = 50 sq m.
⇒A₃ = (20×5) = 100 sq m.
∴A₁ is maximum and A₂ is minimum.
∴Minimum pressure P₁ = F/A₁ = 30/200 = 0.15 Nm⁻².
∴Maximum pressure P₂ = F/A₂ = 30/50 = 0.6 Nm⁻². (Ans)
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Therefore, pressure is maximum when area is minimum and vice versa.
By calculating the area of three faces, we get,
⇒A₁ = (20×10)= 200 sq m.
⇒A₂ = (10×5) = 50 sq m.
⇒A₃ = (20×5) = 100 sq m.
∴A₁ is maximum and A₂ is minimum.
∴Minimum pressure P₁ = F/A₁ = 30/200 = 0.15 Nm⁻².
∴Maximum pressure P₂ = F/A₂ = 30/50 = 0.6 Nm⁻². (Ans)
ALL THE BEST. :)
Answered by
2
Answer:
Maximum pressure is 1/20 Pa whereas minimum pressure is 1/5 Pa
Explanation:
Pressure is the force per unit area. So, P = F/A
Minimum surface area = 5cm×10cm = 50cm
Maximize surface area = 20cm×10cm = 200cm
So, Pressure = Of minimum = f/a
= 10/50 = 1/5 Pa
Of maximum = f/a
= 10/200 = 1/2Pa
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