A block of weight 1 N rests on an inclined plane of inclination "q" with the horizontal . The coefficient of friction between the block and the inclined plane is "u" . The minimum force that has to be applied parallel to inclined plane to make body just move up up the plane is ????? ( answer is " u cos q + sin q " ) pls help
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The minimum force will be equal to the friction and the component of weight in the direction of friction
at first the friction will be opposite of the component of weight but when we will start applying the force due to the friction tendency to oppose the relative motion it will change its direction opposite to that of the direction of force applied
so the force applied should be equal to the maximum static friction and the component of weight
component of weight=sinq
maximum friction =u cosq
the applied force will be =(u cosq +sinq)
at first the friction will be opposite of the component of weight but when we will start applying the force due to the friction tendency to oppose the relative motion it will change its direction opposite to that of the direction of force applied
so the force applied should be equal to the maximum static friction and the component of weight
component of weight=sinq
maximum friction =u cosq
the applied force will be =(u cosq +sinq)
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