Question

A block of weight 100N is slowly slid up on a smooth incline with inclination 37° by a person. Calculate the work done by the person in moving the block thru a distance of 2m, if the driving force is parallel in the horizontal direction. (Given that: sin 37° = 3/5 cos 37° = 4/5)


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Answer 1

Answer:

sin37° = 3/5 and cos 37° = 4/5

let 37° be theta

then

sin theta = 3/5 means perpendicular = 3 and hypotenuse = 5

cos theta = 4/5

means , b /h = 4/5

b= 4 and h= 5

so in total

Explanation:

perpendicular = 3

base = 4

and

hypotenuse = 5