A block of weight 150N is pulled 20m along a horizontal surface at constant
velocity. Calculate the work done by the pulling force if the coefficient of Kinetic
friction is 0.20 and the pulling force makes an angle of 60 with the vertical.
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Answer:
519.6 joule
Explanation:
force resolve into two components
Fsin60 responsible for working
w = coeff. of k. friction x MG x sin60 x distance
w = 0.2 x 150 x sqrt(3)/2 x20
w = 519.6 joule
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