A block of weight G is attached to the axis of a movable pulley. What force should be applied to the ends of the rope passing around the second fixed pulley for the block to move upwards with an acceleration a?
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Answered by
26
T = tension in the rope = force
T + T - G g = G a
So T = (g+a)G/2
See the picture.
T + T - G g = G a
So T = (g+a)G/2
See the picture.
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Answered by
15
Answer:
G here is weight therefore mass of object =G/g
Now , T+T - G =Ga/g
which gives us T = G(a+g)/2g
which is the force required to move the object upward with acceleration a
Explanation:
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