Question

A block of wood floats in a liquid of density of 0.8 g cm cube with four fifth of its volume submerged. Find the density of wood.

Answer 1

Explanation:

Let d be the density of wood,

the wood is submerged 4/5 of its volume, its weight is balanced by buoyant force of water on its 4/5 of volume.

by equilibrium of force

v*d*g = (4/5)*v*0.8*g

d = 3.2/5 = 0.64 gm/cm^3