Physics, asked by parijain20151071, 28 days ago

a block of wood floats in brine solution of density 1.20g cm^-3, such that 3/8 of its value is above brine. calculate the density of wood

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Answers

Answered by ishwarparmar2927
4

Explanation:

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Answered by pateltithi175
3

According to Archimedes' principle.

Mass of volume displaced is by object is buoyancy force.

Let the volume of wood is V.

then the volume submerged in liquid is V/4

let the density of wood be ρ.

let the density of liquid be ρl=0.8cm−3.

weight of wood ρVg.  

buoyancy force =4ρlVg

now weight of block is equal to  buoyancy force.

ρVg=4ρlVg

So ρ=40.8=.2gcm−3

 

then the volume submerged in oil is 60% of is 3V/5

weight of wood ρVg  

buoyancy force =5ρoil3Vg

now weight of block is equal to  buoyancy force.

ρVg=5ρoil3Vg

So ρoil=3ρ×5=30.2×5=0.33gcm−3

 

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