A block of wood has a dimension of 40cm x 20cm x 30cm. Find the pressure if its mass is 10kg
Answers
Answer:
The pressure exerted by the block will be 1225 N/m² or 816.7 N/m² or 1633.3 N/m² according to the position of the block.
Explanation:
The mass of the block, m = 10 Kg
The force exerted by the block, F = ma
Here the acceleration will be equal to the acceleration due to gravity.
∴ F = mg
= 10 × 9.8
F = 98 N
Pressure, P = F/A
Where A is the area of the surface in which the force is applied by the weight of the block.
Pressure when the block is placed with its sides 40 cm and 20 cm.
P₁ = F/A
= 98 / (0.4 × 0.2)
P₁ = 1225 N/m²
Pressure when the block is placed with its sides 40 cm and 30 cm.
P₂ = F/A
= 98 / (0.4 × 0.3)
P₂ = 816.7 N/m²
Pressure when the block is placed with its sides 20 cm and 30 cm.
P₃ = F/A
= 98 / (0.2 × 0.3)
P₃ = 1633.3 N/m²