Question

A block of wood has a mass of 3.6 kg. It's volume is 0.0048 m³.Find the volume of block below the water surface. ​

Answer 1

Explanation:

density of water = 1 g/cm3

density = mass/volume

density of wood = 24000g/32000cm3 = 0.75 g/cm3

The volume of the wood below the water surface is the volume of water displaced. The buoyant force is equal to the weight of the displaced water.

Weight = Mass * acceleration of gravity W = M * g

Let's say wood = d and water = w

The weight of the wood is W(d) = M(d)*g. The buoyant force is equal to the weight of the displaced water, W(w) = M(w)*g

W(d) = W (w)

M(d)*g = M(w)*g

V(d)*density(d) = V(w)*density(w)

V(d)/V(w) = density(w)/density(d)

0.032/V(w) = 1/0.75

V(w) = 0.24 m3

Since the volume of the wood is equal to the volume of water displaced, it is 0.024m3.