A block of wood is floating in water. The portion of block inside the water measures
50cm ×50cm×50cm. What is the magnitude of the buoyant force acting on the wooden
block in SI unit? [g = 10 msec-2
]
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Answer:
Density of water, ρ=1000 kg m
−3
According to Archimedes principle, the buoyant force acting on an object is equal to the weight of the liquid displaced.
Volume of water displaced = 50×50×50×10
−6
m
3
=0.125 m
3
Weight of water displaced = 0.125×1000×9.8=1225 N
X=1225
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