Question

A block of wood is floating in water. The portion of the block inside water measures 50 cm * 50 cm - 50 cm. What is the magnitude
of the buoyant force acting on the block? (Take density of water as 1 g cm-3)
(Ans. 1250 N)
​

Answer 1

Answer:

Density of water, ρ=1000 kg m

−3

According to Archimedes principle, the buoyant force acting on an object is equal to the weight of the liquid displaced.

Volume of water displaced = 50×50×50×10

−6

m

3

=0.125 m

3

Weight of water displaced = 0.125×1000×9.8=1225 N

X=1225