Question

A block of wood is floating on water with its dimensions 50cm * 50cm* 50cm inside water. Calculate the buoyant force acting on the block. Take g=9.8 N kg-1

Answer 1

Answer:

X=1225

Explanation:

Density of water, ρ=1000 kg m  

−3

 

According to Archimedes principle, the buoyant force acting on an object is equal to the weight of the liquid displaced.  

Volume of water displaced = 50×50×50×10 POWER OF -6

Weight of water displaced = 0.125×1000×9.8=1225 N

X=1225