Question

A block of wood is floating on water with its dimensions 50cm×50cm×50cm inside water. Calculate the buoyant force acting on the block.Take g=9.8NKg^-1 ​

Answer 1

answe

Density of water, ρ=1000 kg m

−3

According to Archimedes principle, the buoyant force acting on an object is equal to the weight of the liquid displaced.

Volume of water displaced = 50×50×50×10

−6

m

3

=0.125 m

3

Weight of water displaced = 0.125×1000×9.8=1225 N

X

Density of water, ρ=1000 kg m

−3

According to Archimedes principle, the buoyant force acting on an object is equal to the weight of the liquid displaced.

Volume of water displaced = 50×50×50×10

−6

m

3

=0.125 m

3

Weight of water displaced = 0.125×1000×9.8=1225 N

X=1225