Question

A block of wood is kept on a table top. The mass of the wooden block is 5 kg and its dimensions are 40 cm x 20 cm x10 cm. Find the pressure exerted by the wooden block on the table top if it is made to lie on the table with its sides of dimensions 20 cm x 10 cm​

Answer 1

Answer:

p=612.5N.m-²

P=2450N.m–²

Step-by-step explanation:

Mass of the wooden block, m=5kg

Thrust due to wooden block,

Mg=5kg×9.8ms

−2

=49N

(a) Surface area of 20cm×10cm surface,

A=(20×10)cm2

=(0.2×0.1)m2

=0.02m2

P= A/mg

P= 0.02m2/49N

= 0.02/49 Nm −2

or Pressure, P=2450Nm −2

.

(b) Surface area of 40cm×20cm surface,

A=(40×20)cm2

=(0.4×0.2)m2

=0.08m 2

P= 0.08m2/49N

= 0.08/49Nm −2

or Pressure, P=612.5Nm

−2

.