a block of wood mass 6kg and dimensions 50cm×30cm×20cm is placed on table top find the pressure exerted if blockages on table top with sides of dimensions
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P=F/A
F=mg = 6x9.8=58.8N
A=(50x30x20)/10^6=0.03m^2
P=58.8/0.03=1960N/m^2 if I'm not wrong
F=mg = 6x9.8=58.8N
A=(50x30x20)/10^6=0.03m^2
P=58.8/0.03=1960N/m^2 if I'm not wrong
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ans is 1980 N/m^2 . hope this helps you
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