Math, asked by shambhavi9035, 4 months ago

A block of wood measuring 12cm by 16 cm by 8cm is cut into cubical blocks of the same size . Find the number of cubical blocks if each side measures 4cm.

Answers

Answered by Ladylaurel
10

Answer :-

  • Number of blocks required is 24 blocks.

Step-by-step explanation :

To Find :-

  • The number of cubical blocks.

Solution :-

Given that,

  • Side of a cubical box = 4cm

Dimensions of the cuboidal wood = 12cm*16cm*8cm.

  • Length = 12cm
  • Breadth = 16cm
  • Height = 8cm

Hence, the volume of cuboidal wood, As we know that,

Volume of cuboid = lbh,

Where,

  • l = Length
  • b = Breadth
  • h = Height

=> Volume = l × b × h

=> 12cm × 16cm × 8cm

=> ( 12 × 16 × 8 ) cm³

=> ( 192 × 8 ) cm³

=> 1536 cm³

The volume of cubical block, As we know that,

Volume of cube = ,

Where,

  • a = side of cube

=> Volume = a × a × a

=> 4cm × 4cm × 4cm

=> ( 4 × 4 × 4 ) cm³

=> ( 16 × 4 ) cm³

=> 64cm³

Now, the number of cubical blocks. As we know that,

Number of blocks = Volume of cuboid ÷ Volume of cube,

=> 1536 ÷ 64

=> 24.

Hence,

  • Number of blocks required is 24 blocks.
Answered by SuitableBoy
149

\large{\underbrace{\underline{\bf{Required~Answer:-}}}}

 \\

\frak{Given}\begin{cases}\sf{Dimensions\:of\:block=\bf{12cm}\:by\:\bf{16cm}\:by\bf{8cm.}}\\\sf{Side\:of\:a\:cubical\:block=\bf{4cm.}}\end{cases}

 \\

\bigstar\:\underline{\textit{\textbf{To\:Find:}}}

 \\

  • Number of cubical block that can be made.

 \\

\star\;\underline{\textit{\textbf{Solution:}}}

 \\

» We would first find the volume of the wooden block.

» Then we would find the volume of the cubical block.

» Then we would divide the volume of wooden block by the volume of the cubical block so as to get the answer.

 \\

Finding the Volume of wooden block -

 \\

  • Length = 16 cm
  • Breadth = 12 cm
  • Height = 8 cm

» Using the formula to find the volume of a cuboid.

 \odot \:  \boxed{ \sf \: Volume _{ \: Cuboid} = Length \times Breadth \times Height}

So,

 \colon \rarr \sf \: Volume _{ \: (Wooden \: Block)} = 16 \times 12 \times 8 \:  {cm}^{3}  \\  \\  \colon \dashrightarrow \underline{ \boxed{ \pink{ \frak{Volume _{ \: (Wooden \: Block)} =1536  \: {cm}^{3}  }}}}

 \\

Finding the Volume of cubical block -

 \\

  • Side of the cubical block = 4 cm.

» Using the formula to find the volume of cube.

 \odot  \: \boxed{ \sf{Volume _{ \: Cube} =  {side}^{3} }}

So,

 \colon \rarr \sf \:  Volume _{ \: (Cubical \: Block)} =   {(4 \: cm)}^{3}  \\  \\  \colon \rarr \sf \: Volume _{ \: (Cubical \: Block)} = 4 \times 4 \times 4 \:  {cm}^{3}  \\  \\  \colon \dashrightarrow \underline{  \boxed{ \pink{ \frak{Volume _{ \: (Cubical \: Block)} = 64 \:  {cm}^{3}}}}}

 \\

Finding the number of blocks -

 \\

 \colon \leadsto \sf \: No. \: of\: blocks =  \frac{Volume \: of \: Wodden \: block}{Volume \: of \: cubical \: block}  \\  \\  \colon \leadsto  \sf \: No. \: of \: block =  \cancel \frac{1536 \:  {cm}^{3} }{64 \:  {cm}^{3} }  \\  \\  \colon \dashrightarrow \underline{ \boxed{ \bf{ \red{No. \: of \: blocks = 24}}}}

 \\

\therefore\;\underline{\sf Number \;of \;Cubical\;blocks\;formed=\bf{24.}}

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