A block of wood of density 0.8 g cm cube has a volume of 60 cm cube. The mass of block will be
Answers
According to Archimedes' principle.
Mass of volume displaced is by object is buoyancy force.
Let the volume of wood is V.
then the volume submerged in liquid is V/4
let the density of wood be ρ.
let the density of liquid be ρ
l
=0.8cm
−3
.
weight of wood ρVg.
buoyancy force =
4
ρ
l
V
g
now weight of block is equal to buoyancy force.
ρVg=
4
ρ
l
V
g
So ρ=
4
0.8
=.2gcm
−3
then the volume submerged in oil is 60% of is 3V/5
weight of wood ρVg
buoyancy force =
5
ρ
oil
3V
g
now weight of block is equal to buoyancy force.
ρVg=
5
ρ
oil
3V
g
So ρ
oil
=
3
ρ×5
=
3
0.2×5
=0.33gcm
−3
Answered By
toppr
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Answer:
48kg
Explanation:
Formula
mass=volume x density
48 =60 x 0.8
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