A block of wood of density 500 kg//m^(3) has mass m kg in air. A lead block which has apparent weight of 28 kg in water is attached to the block of wood, and both of them are submerged in water. If their combined apparent weight in water is 20 kg, find the value of m. Take density of water =1000kg//m^(3)
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Answer:
S
1
V
1
+S
2
V
2
−S
w
(V
1
+V
2
)=20⟶(2) S
1
V
1
g−S
w
V
1
g=28g
⇒(S
1
V
1
−S
w
V
1
)+S
2
V
2
−S
w
V
2
=20 V
1
(S
1
−S
w
)=28⟶(1)
⇒28+500V
2
−1000V
2
=20 S
1
V
1
−S
w
V
1
=28
⇒28−500V
2
=20
⇒500V
2
=8
⇒V
2
=
500
8
m
3
mass of wooden block =S
2
V
2
=500×
500
8
=8kg.Explanation:
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