Question

A block of wood of density 600kgm^-3 and volume 0.6 m^3 floats in water of density 1000 kg m^-3 .How much of it is below water level?​

Answer 1

Answer:

D1 × V1 = D2 × V2

600×0.6 = 1000×V2

360 = 1000V2

V2 = 360/1000

V2 = 0.36

Therefore, 0.36m³ is below water level

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