A block of wood of maa 9.8kg is suspended by a string .A bullet of mass 200gm strikes horizontally with a velocity of 100 m/s and gets imbedded init .The maximum height attained by the block is
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first conserve momentum just at that instant and then use energy conservation
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Answer:0.2m
Explanation:mu+Mu'=(M+m)v
m=mass of block
M=mass of bullet
u=initial velocity of block
u'=initial velocity of bullet
v=final velocity of system
9.8(0)+0.2(100)=(9.8+0.2)v
v=2
h=v^2/2g
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