Question

A Block of wood of mass 2.6 kg is moved up along
8.9 m incline from rest by applying
a horizontal
force of 25N . if the incline makes
an angle of
23°
with the horizontal
and the total work done on
block to move it up the i5 78.9 J calcuate the
magnitude of frictional force between wood and the
incline​

Answer 1

Answer:

ANSWER

Mass of the block m=8 kg

Acceleration of the block a=0.4m/s

2

Since the block is sliding down the plane, so friction force acts backwards as shown.

Equation of motion along the inclined plane :

ma=mgsin30

o

−f

We get f=mgsin30

o

−ma

∴ f=(8)(10)(0.5)−(8)(0.4)

⟹f=36.8 N

Explanation:

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