Question

A block of wood whose density and volume are 780 kg.m-3 and 200 cm3 respectively floats in a brine solution of density 1040 kg.m-3 . What volume of the wooden block remains above the surface of brine?

Answer 1

Answer:

so ans is kg

Explanation:

Here, mass m=100kg,

density ρ=500kgm

−3

Volume of the body, V=

ρ

m

=

500

10

=0.2m

3

Weight of water displaced

=Vρg

=0.2×10

3

×g

=200gkgwt

Mass of water displaced =200kg

∴ the additional mass which can be added to body, so that body can sink

=200−100=100kg