A block on a long table is tied by massless ropes to two hanging blocks as in figure. Initially
block C is moving downwards with non zero velocity. The static and kinetic friction between
block B & table is 0.3 and 0.1 respectively.
AD
m=1kg
m=2kg
me=20kg
(A) Acceleration of block C is approx. 0.4 m/s2 downwards
(B) Acceleration of block C is approx. 0.43 m/s2 upwards
(C) Block C comes to rest after some time
(D) Acceleration of block C is zero, all the time
Answers
Answer:
D
Step-by-step explanation:
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Answer:
The acceleration of block C can be determined using the equations of motion for the system. Since block C initially moves downwards with a non-zero velocity, we can assume that the net force acting on it is not zero.
Step-by-step explanation:
The force acting on block C can be broken down into two components: the force exerted by block B and the force exerted by block A. The force exerted by block B on block C equals the force of static friction between block B and the table. Since the coefficient of static friction is 0.3, the force exerted by block B is 0.3 * 20kg * 9.8m/s^2 = 58.8 N, upwards.
The force exerted by block A on block C equals the tension in the rope connecting block A and block C. The tension in the rope is equal to the force of gravity acting on block A, which is 1kg * 9.8 m/s^2 = 9.8 N, downwards.
The net force acting on block C is the vector sum of the forces exerted by blocks B and A.
Fnet = FblockB + FblockA = 58.8 N, upwards + 9.8 N, downwards = 48 N, downwards
The acceleration of block C can be determined using the equation Fnet = ma.
a = Fnet / m = 48 N / 20 kg = 2.4 m/s^2 downwards.
Therefore, the correct option is A. Acceleration of block C is approx. 0.4 m/s^2 downwards.
To learn more about motion, click on the link below.
https://brainly.in/question/54130140
To learn more about velocity, click on the link below.
https://brainly.in/question/54106151
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