A block P of mass 10 kg is lying on a rough
horizontal table and another block Q hangs
vertically with the help of ideal string as shown in the
figure. If coefficient of friction between the table and
block is 0.4, then maximum mass of block Q for
which the system will be stationary is
(1) 6 kg
(3) 8 kg
(2) 8 kg
(4) 2 kg
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Given:
A block P of mass 10kg is lying on a rough horizontal table
block Q hangs vertically with the help of ideal string
coefficient of friction between table and block is 0.4
To Find:
Maximum mass of block Q for which the system will be stationary
Solution:
Free body diagram of block P
F(net) = 0
T = .4(N)
force in vertical direction
N = mg (take g = 10)
T = .4(10)(10)= 40 N
resolve tension in the inclined spring in vertical and horizontal direction
T sin45 = Mg
T =
Mass of block Q is 2.82 kg
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