Question

A block placed on a rough inclined plane of length 4 just begins to slide down on the upper end of the plane is 1 m high from the ground calculate the coefficient of static friction

Answer 1

let x be the angle of the inclined.
So sinx= 1/4
cosx=√(1-sin^2A)= √1-1/16=√15/4
hence coefficient of static friction= tanx= sinx/ cosx=1/√15

Answer 2

"The perpendicular height of the block with respect to ground is 1 m

The inclined plane of length = 4 m

Static friction = tan thetha = 1/base

Tan thetha = 1/ square root (4^2 – 1^2)

Tan thetha = 1/ square root (16 – 1)

Tan thetha = 1/ square root (15)

Tan thetha = 0.258

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