Physics, asked by mukulgupta9952, 10 months ago

A block Q of mass M is placed on a horizontal frictionless
surface AB and a body P of mass m is released on its
frictionless slope. As P slides by a length L on this slope of
inclination ϴ, the block Q would slide by a distance
(a) (m/M) L cos ϴ (b) m L/(M + m)
(c) (M + m)/(m L cos ϴ) (d) (m L cos ϴ) / (m + M)

Answers

Answered by yashwanthyedla2007
0

Explanation:

A block Q of mass M is placed on a horizontal frictionless

surface AB and a body P of mass m is released on its

frictionless slope. As P slides by a length L on this slope of

inclination ϴ, the block Q would slide by a distance

(a) (m/M) L cos ϴ (b) m L/(M + m)

(c) (M + m)/(m L cos ϴ) (d) (m L cos ϴ) / (m + M)

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