Question

A Block rest on a rough inclined plane making an angle of 30° with the horizontal.The coefficient of static friction between the block and the plane .8 . If the frictional force is 10 Newton, mass of the block in kilogram is ?

Answer 1

See the attached image for explanation. Please mark it as brainliest if it helps.

Answer 2

"The mass of the block in kilogram is 2 kg.

Solution:

We know that static friction is self-adjusting force

Moreover, it changes itself with respect to the applied force.

The "static friction force" is always equal to "net external force" i.e., F = P

For an equilibrium block, it is consider that,

Friction force = 10 N

Coefficient of static friction = 8

Angle of inclination = 30°

${ F }\quad =\quad { mg }\sin{ \theta}$

Since, the mass is acting in vertical direction sine is considered.

$\therefore \quad 10\quad =\quad m\quad \times \quad 10\quad \times \quad \sin{ 30 }$

$\because \quad \sin { 30 } \quad =\quad \frac { 1 }{ 2 }$

On simplifying we get, m = 2 kg"