Question

A block slides down a frictionless incline ramp .if a ramp if at angle of 17.0 and its length is 30 ,find the speed of the block as it reaches the bottom of the ramp,assuming it started sliding from rest at the top

Answer 1

Answer:

Here,

 h=5m

g=10ms−2

Using conservation of energy:

mgh=0.5×mv2

10×5=0.5×v2

v=100=10 m/s

Answer 2

Answer:

The mechanical energy of a system acted upon by conservative forces (like gravity) and by other external forces that do not produce work (such as forces acting normal to the path of the motion) remains conserved: {eq}KE_i + PE_i = KE_f + PE_f {/eq} KEi+PEi=KEf+PEfKEi+PEi=KEf+PEf

The formula of the potential energy due to gravity and of the kinetic energy is as follows :

Potential Energy due to gravity: {eq}PE = mgh {/eq} PE=mghPE=mgh

Kinetic Energy: {eq}KE = \frac{1}{2}mv^2 {/eq} KE=12mv2KE=12mv2

h = height

m = mass

g = acceleration due to gravity

v = speed

Answer and Explanation

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