Question

A block slides down a frictionless plane that makes an angle of 30° with the horizontal. The acceleration of the block is:

Group of answer choices

9.80 m/s2


8.49 m/s2


0 m/s2


5.66 m/s2


4.90 m/s2​

Answer 1

The acceleration of a block sliding down a frictionless plane that makes an angle $\theta$ with the horizontal is given by,

• $\sf{a=g\sin\theta}$

where $\sf{g}$ is the acceleration due to gravity equal to $\sf{9.80\ m\,s^{-2}.}$

In this question,

• $\sf{\theta=30^o}$

Then,

$\sf{\longrightarrow a=g\sin\theta}$

$\sf{\longrightarrow a=9.80\sin30^o}$

$\sf{\longrightarrow a=9.80\times\dfrac{1}{2}}$

$\sf{\longrightarrow\underline{\underline{a=4.90\ m\,s^{-2}}}}$

Answer 2

Answer:5

Explanation: