A block slides down an inclined surface of inclination 30° with the horizontal. Suppose the block of this problem is pushed down the incline with a force of 4 N. How far will the block move in the first two seconds after starting from rest? The mass of block is 4 kg. ?
Answers
Answered by
12
Refer this link for the first part,
https://brainly.in/question/6141260
Net Force acting on the Incline = 4 + mgsin30 - friction
= 4 + 20 - μmgcos30
= 24 - 0.11 × 10 × 4 × √3/2
= 24 - 4
= 20 N
∴ ma = 20
⇒ a = 5 m/s².
Now, The displacement covered by the man in 2 seconds,
S = ut + 1/2 × at²
⇒ S = 1/2 × 5 × 4
∴ S = 10 m.
Hope it helps.
Answered by
0
Answer:10
Explanation:
Refer 6 th question
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