Question

A block sliding down an rough 45degree inclined plane has half the velocity it would have had the inclined plane been smooth the coefficient of sliding friction

Answer 1

Given :

A block is sliding in a rough inclined plane has half its velocity (v/2).

Acceleration down = [g (sin●- ¤cos●)]

Here ●=they a

¤=knew

Answer 2

WE SHOULD HAVE THE KEY POINT OF THIS QUESTION THAT-

1. For Smooth inclined plane, net acceleration= g sin theta (only, as there is negligible friction)

2.For Rough inclined plane, net acceleration= g sin theta - mew. cos theta