Question

a block start sliding on a rough horizontal surface with a velocity of 8m/s having the coefficient of friction 0.4 find disrance travelled in 5 sec​

Answer 1

Answer:

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Answer 2

Answer:

The distance traveled is 8.16 m.

Explanation:

Given that,

Coefficient of friction = 0.4

Velocity = 8 m/s

Time = 5 sec

We need to calculate the distance

Using change in kinetic energy

$\dfrac{1}{2}mv^2=\mu\times mgx$

Where, $\mu$ = coefficient of friction

g = acceleration due to gravity

v = velocity

Put the value into the formula

$\dfrac{1}{2}\times8^2=0.4\times9.8\times x$

$x=\dfrac{8^2}{2\times0.4\times9.8}$

$x=8.16\ m$

Hence, The distance traveled is 8.16 m.