Question

A block tied between two springs is in equilibrium.
If upper spring is cut then the acceleration of the
block just after cut is 6 m/s2 downwards. Now, if
instead of upper spring, lower spring is cut then the
magnitude of acceleration of the block just after the
cut will be : (Take g = 10 m/s2)
​

Answer 1

Answer:

The  magnitude of acceleration of the block just after the  cut will be 4 m/s^2

Explanation:

The block has is tied with two springs

let spring one is x1 and spring two is x2

x1+x2=mg  ...(i)  [ where m is the mass and g is the gravitational force]

Let the acceleration is a

Now if upper spring is cut  

a=mg−x1/m    =6 [ as g= 10 m/s^2]

Therefore x1=4m  

If lower spring is cut

x2=6m  

a=mg−x2/m

=10m−6m/m

   =4 m/s^2