Question

A block weighing 10 N travels down a smooth curved track AB joined to a rough horizontal surface (figure 8-E5). The rough surface has a friction coefficient of 0⋅20 with the block. If the block starts slipping on the track from a point 1⋅0 m above the horizontal surface, how far will it move on the rough surface?
Figure

Answer 1

The block weighing 10 N travels down a smooth curved track AB joined to rough horizontal surface with friction of coefficient 0.20 will travels around  5 m around the rough surface.

Explanation:

Step 1:

given data in the question  

μ = 0.2 ,  

h = 1 m ,  

mg = 10 N  

Step 2:

Potential Energy with respect to ground = mgh

Potential energy = 10 × 1

Potential energy  = 10 J.

Frictional force on the rugged surface here

$F = \mu \times R$

F = 0.2 × 10  [ In this case R equals mg ]

F = 2 N.

Step 3:

Suppose the distance S is shifted on the rough track, Then work done by force  is given by

Work done = Force × Displacement

W = F × S

$S =\frac{W}{F}$

$S = \frac{10}{2}$

S = 5 m.  

Thus the block travels around 5 m on the rough surface.

Answer 2

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