Question

A block weighing 1200 N rests on an area of 6 square meter calculate the pressure exerted by block on the surface which supports it.

Answer 1

Answer:

200 N m^2

Explanation:

Given there is a block.

It's kept on to rest on an area.

Weight = 1200 N

Area on which it rests = 6 sq. m

To find the pressure exerted by the block.

We know that,

Pressure = Force/Area

Here, the force will be equal to the weight of the block, i.e, 1200 N.

Therefore, we will get,

=> p = 1200/6

=> p = 200

Hence, required pressure is 200 N m^2.

Some more information:-

• SI unit of pressure is known as Pascal, denoted by Pa.
• Pressure is also measured in atm, torr, column of mercury.

Answer 2

Given

• Force = 1200 N
• Area of block = 6m²

Find out

• Calculate the pressure exerted by block

Solution

As we know that

$\implies\sf Pressure=\dfrac{Force}{Area} \\ \\ \\ \implies\sf P=\cancel\dfrac{1200}{6} \\ \\ \\ \implies\sf P=200N/m^2$

Hence, the pressure exerted by block is 200N/m²

Additional Information

• Force acting on a perpendicular direction to unit surface area is known as pressure.
• Its S.I unit is N/m²(Pascal)