A block weighing 50 N is resting on a horizontal plane A horizontal force of 10 N is applied to start the sliding the block find
Angle of friction (m) Resultant force.
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Answer:
See Beelow
Explanation:
a. F
fric
=μ
s
W=0.4∗20=8N
b. Since F
applied
<F
fric
F
fric
=5N
c. Minimum force required to start the motion F=F
staticfric
=8N
d. Minimum force required to start the motion
F=F
kineticfric
=μ
k
W=0.2∗20=4N
e. F>F
staticfric
motion started.
F>F
kineticfric
hence motion continues.
F
fric
=4N
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