A block weighing 981 n is resting on a horizontal surface. The coefficient of friction between the block and the horizontal surface is = 0.2. A vertical cable attached to the block provides partial support as shown. A man can pull horizontally with a force of 100n. What will be the tension, t (in n) in the cable if the man is just able to move the block to the right?
Answers
Answered by
1
Answer:
481 newton
Explanation:
Let the Normal reaction be 'N'
so, 100 = 0.2 × N
N = 500
now,
Tension + N = 981
Tension + 500 = 981
Tension = 481newton
Answered by
0
Answer:
T= 481N
Explanation:
Balancing the forces in the horizontal and vertical direction:
Horizontal:=
£Fx =0
ûR = 10
(0.2)R= 100
R = 500N
Vertical :=
£Fy =0
T+R-W =0
T+500-981 =0
T = 481N
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