Question

A block weighing 981 n is resting on a horizontal surface. The coefficient of friction between the block and the horizontal surface is = 0.2. A vertical cable attached to the block provides partial support as shown. A man can pull horizontally with a force of 100n. What will be the tension, t (in n) in the cable if the man is just able to move the block to the right?

Answer 1

Answer:

481 newton

Explanation:

Let the Normal reaction be 'N'

so, 100 = 0.2 × N

N = 500

now,

Tension + N = 981

Tension + 500 = 981

Tension = 481newton

Answer 2

Answer:

T= 481N

Explanation:

Balancing the forces in the horizontal and vertical direction:

Horizontal:=

£Fx =0

ûR = 10

(0.2)R= 100

R = 500N

Vertical :=

£Fy =0

T+R-W =0

T+500-981 =0

T = 481N