A block weighing W is resting on a plane inclined at q to the horizontal. The
coefficient of friction is m. The force P required to pull it up the plane is
aW
(a) W sin q - mW cos q
O
(b) W sin q + m W cos q
0 q
(c) W cos q- mW sin q
0 (d) W cos q + m W sin q
Answers
Answered by
1
Answer:
In the limiting case contact force F is inclined at λ to the normal. Only three forces act on the block.
Applying Lami's theorem, we get:
sin(180
∘
−λ)
P
=
sin(90
∘
−θ+λ)
W
sin(90
∘
+θ)
F
or
sinλ
P
=
cos(θ−λ)
w
or P=
cos(θ−λ)
W
P will be least when cos(θ−λ) is greatest because W and λ are constant.
i.e., when cos(θ−)=1 and θλ=0
∘
or θ=λ
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